a solution should contain 2 onces of cemical for every 7 once of water. how much cemical should be added to 20 once of water to get the proper concentration.?
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Answer:
It can be solved by equal proportionality theorem.
Step-by-step explanation:
Let amount of chemical be x.
2 : 7 : : x : 20
7x = 2 × 20
x = 40/7
x = 5.7 once
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