Question

A solution was prepared by dissolving certain amount of compound in 31.8 g of !! has a

boiling point of 0.392 K higher than that of pure !!. If the molar mass of compound is 128 g



, calculate the mass of the solute dissolved. (Given $% !! = 5.02 ​

Answer 1

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ANSWER

K

b

of water =1.87

morality of solute =

m×500/1000

34.2

=

m

342×2

(∵ morality : mole of solute mass of solvent (kg)) (m = m: water of solute)

Elevation in boiling point = morality ×K

b

Elevation =100.104−100=0.104

So .104=

m

34.2×2

=m=1229.88

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Answer 2

Conclusion

What is a Compound?

Compound. [kŏm′pound′] is a substance made up of molecules, which are made up of atoms or ions of two or more distinct elements in specific ratios. Physically, the elements cannot be separated. One molecule of water, for instance, contains one oxygen atom and two hydrogen atoms.

Main content

In 1st case

$w_2 = 0.8g$

$M_2$ of naphthalene $C_{10}H_8 = 128$

$w_1 = 100g\\\triangle T_b = 0.4^0 C\\\triangle T_b = K_bm$

Where m is the morality

$K_b =$ Moral elevation constant

$\triangle T_b = K_b\frac{w_2 \times 1000}{M_2 w_1} \\Kb=\frac{128\times0.4}{8} = 6.4 K Kg mol^-$

In 2nd Case

$w_2 = 1.24g\\w_1 = 100g\\K_b = 6.4 K Kg mol^-\\\triangle T_b = 0.62^0 C\\M_2 = \frac{1.24\times 6.4\times 10}{0.62} = 128g$

To learn more about Compound

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