Question

A solution with ph 2.0 is more acidic than the one with ph 6 by what factor

Answer 1

since ph is -log ([H+])) to the base 10...so the difference results in 10000

Answer 2

Step-by-step explanation:

3⋅2

3

2

(

3

3

2085

+137

+

3

137−3

2085

+

3

2

)

≈10.5817164

$⋅232(332085+137+3137−32085+32)≈10.581716493$

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