Biology, asked by StarTbia, 1 year ago

A solution x contains 30 mole percent of A and is equilibrium with its vapour that contains 40 mole percent of B. the ratio of vapour pressure of A and B will be

Answers

Answered by aqibkincsem
11
PA = yA x Ptotal

 PB = yB x Ptotal ; yB is mole fraction B in VAPOR phase

 Subbing values we get,

yA x Pt = (P*A) x (χA)

yB x Pt = (P*B) x (χB)

Dividing these equations we get

(yA / yB) x (Pt / Pt) = (P*A / P*B) x (χA / χB)

simplifying and rearranging

(P*A / P*B) = (yA / yB) x (χB / χA)

(P*A / P*B) = (60 / 40) x (70 / 30) = 3.5

 Ratio of pure a and b = 3.5 
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