Question

A solutionof glucose( molar mass= 180g mo/l ) in water is labelled as 10% by mass.
What would be the molality of the solution?

Answer 1

Mass of Glucose = 10g

Moles of Glucose = $\dfrac{Mass \:of\: Glucose}{Molecular \:Mass}$

Molecular mass of Glucose = 180 (Given)

= $\dfrac{10}{180}$

= 0.0556

Mass of water = 90 g

Molality = $\dfrac{Moles \:of\: Glucose}{Mass\: of \:water}$

= $\dfrac{0.0556}{90}$ × 1000

= 0.618 m.

Answer 2

${\textbf{\underline{\red{Given:-}}}}$

Mass of Glucose = 10g

Molecular mass of Glucose = 180g

${\textbf{\underline{\red{To\:Find:-}}}}$

What would be the molality of the solution.

${\textbf{\underline{\red{Solution:-}}}}$

$\bf {Moles\: of \:Glucose = \dfrac{Mass \:of\: Glucose}{Molecular \:Mass} }$

$\bf :\implies \dfrac{10}{180}$

$\bf :\implies 0.0556$

Mass of water = 90 g

$\bf Molality = \dfrac{Moles \:of\: Glucose}{Mass\: of \:water}$

$\bf :\implies \dfrac{0.0556}{90}$

$\bf :\implies {\boxed{0.618 m}}$