Question

a Solve 8x²-2x - 3=0 with completing
square Method​

Answer 1

Answer:

Dividing both sides by 2

$4 {x}^{2} - x - \frac{3}{2} = 0$

$(2x) {}^{2} - 2 \times 2x \times \frac{1}{4} + ( \frac{1}{4} ) {}^{2} - \frac{3}{2} - \frac{1}{16} = 0$

$(2x - \frac{1}{4} ) {}^{2} - \frac{24 + 1}{16} = 0$

$(2x - \frac{1}{4} ) {}^{2} = \frac{25}{16}$

$2x - \frac{1}{4} = \frac{5}{4} \: \: or \: - \frac{5}{4}$

$2x = \frac{3}{2} \: \: or \: \: - 1$

$x = \frac{3}{4} \: \: or \: \: - \frac{1}{2} \: \: ans.$