Question

a-
Solve for a
(a-2)+1\a-2 =3,where a not equal to 2​

Answer 1

(a-2)^2+1= 3* (a-2). While we cross multiply
(a-2)^2 = a^2 +4_4a
So (a-2)^2+1 = a^2 +4_4a

a^2 +4_4a+1= a^2 +5_4a
So a^2 +5-4a= 3a-6

a^2 +5_4a-3a+6=0

a^2 -7a+11=0
Now a=