a-
Solve for a
(a-2)+1\a-2 =3,where a not equal to 2
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(a-2)^2+1= 3* (a-2). While we cross multiply
(a-2)^2 = a^2 +4_4a
So (a-2)^2+1 = a^2 +4_4a
a^2 +4_4a+1= a^2 +5_4a
So a^2 +5-4a= 3a-6
a^2 +5_4a-3a+6=0
a^2 -7a+11=0
Now a=
(a-2)^2 = a^2 +4_4a
So (a-2)^2+1 = a^2 +4_4a
a^2 +4_4a+1= a^2 +5_4a
So a^2 +5-4a= 3a-6
a^2 +5_4a-3a+6=0
a^2 -7a+11=0
Now a=
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