A) Solve for x: a. (3x+2/ 7) + (4(x+1)/ 5) = 2 /3 (2x+1) b.(2x−10 /20) + (4x+5 /13) = 6 B) Solve for ‘t’ :( 3t−7/ 5) − (t+1 /6 ) =( 2t+2/ 12) - 1
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