a. solve the following equations graphically - ... 3x -2y = 0 , 4x - y -5 = 0 . b. find the areas formed by these lines on X axis .
c. also find the areas formed by these lines on Y axis .
d. calculate the ratio between the 2 areas . plz plz answer it plzzzzzzzzzz and fst
HARSH08:
Plzz i need a writen answer
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See diagram enclosed.
First make a table of points for each straight line. find y for x = 0,1,2,-1, etc. Find the point at which y = 0 too.
Area formed by the lines L1 and L2 with X-axis is the triangle OAB.
Area = 1/2* height * base OB = 1/2 * 3 * 5/4 = 15/8
Area formed by the lines L1 and L@ with the Y - axis is the triangle OAC.
Area = 1/2 * base OC * height = 1/2* 5 * 2 = 5
Ratio of area on Y axis / area on X axis = 5 /(15/8) = 8/3
First make a table of points for each straight line. find y for x = 0,1,2,-1, etc. Find the point at which y = 0 too.
Area formed by the lines L1 and L2 with X-axis is the triangle OAB.
Area = 1/2* height * base OB = 1/2 * 3 * 5/4 = 15/8
Area formed by the lines L1 and L@ with the Y - axis is the triangle OAC.
Area = 1/2 * base OC * height = 1/2* 5 * 2 = 5
Ratio of area on Y axis / area on X axis = 5 /(15/8) = 8/3
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sorry bro but I need a points so I am giving same answer
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