Question

a) Solve the quadratic equation 1/a+b+x=1/a+1/b+1/x,
a+b not equal to 0 by factorization method.
If the equations x2 + kx + 64 = 0 and x2 - 8x + k= 0
have real roots, find the positive values of k.​

Answer 1

I couldn't understood what you meant by a+b = 0 and the answer to third part is as following

If,

x²+kx+64=0 and x²-8x+k=0 have real and distinct roots, then

b²>4ac

In equation 1,

k²> 4.1.64

k> √2²×8²

k> 2×8=16

Similarly,in equation 2

(-8)²> 4.1.k

64> 4k

k>16

Therefore for both the situation k will be acceptable for any value greater than 16.

Answer 2

Answer:

x=-a and -b

for step by step explanation, pls find attachment

k=16