Math, asked by jeevicacchhibber, 5 months ago

a solve this math sum pls it's urgent ​

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Answered by nishtha2504
2

Answer:

no. of tiles required= area of wall ÷ area of tile

= 400 cm x 300 cm / 12 cm x 10 cm

= 120000 cm^2/ 120 cm^2

= 1000 tiles.

each tile costs 22.50 rs.

total cost = 1000 x 22.50 Rs.

= Rs. 22500

Hope this helped. Good luck!

Answered by Anonymous
3

★Given that,A marble tile measures 12cm×10cm.

☯️To Find: how many tiles will be required to cover a wall of 4m by 3m and the total cost if each tile costs Rs.22.50

__________________________________________

  \sf \underline{★According \: to \: the \: question: }

 \tt \blue{area \: of \: te \: wall : }length \times breadth \\   \\ \tt \blue{area \: of \: te \: wall : }3m \times 4m \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:   \\  \\  \tt \blue{area \: of \: te \: wall : }12 {m}^{2}   \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \: \\  \\  \blue{ \boxed{  \orange{ \mathfrak{ \therefore \: area \: of \: the \: wall = 12 {oooocm}^{2} }}}}  \\  \\  \\  \tt \pink{area \: of \: a \: tile  : } length \times breadth \\  \\ \tt \pink{area \: of \: a \: tile  : }12cm \times 10cm \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\ \tt \pink{area \: of \: a \: tile  : }120 {cm}^{2}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\  \\ \blue{ \boxed{  \purple{ \mathfrak{ \therefore \: area \: of \: the \: tile = 12 {ocm}^{2} }}}}

now, the number of tiles can be fitted:

⟼120000 \div 120 \ \\  \\ \ ⟼ \cancel \frac{120000}{120}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\ \sf  = 1000tiles \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

\blue{ \boxed{  \pink{ \mathfrak{ \therefore 1000 \: tiles \: can \: be \: fitted \: in \: the \: wall }}}}

total cost:22.5×1000=Rs.22500

hope this helps.!

#be brainly

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