Question

A son's present age is half the present age of his mom. Ten years ago, the mother's age was thrice the age of son. What are the present ages of both? ​

Answer 1

Answer:

Step-by-step explanation:

Let the present age of the mother be x years

As the son's age is half the present age of his mother, therefore,

the present age of the son = 1/2x years

Ten years ago,

the age of the mother = (x-10) years

and the age of the son = (1/2x - 10) years

According to the problem ,

x - 10 = 3(1/2x - 10)

=> x - 10 = 3/2x - 30

=> 2x - 20 = 3x - 60 (multiplying both sides by 2)

=> 2x - 3x = 60+20

=> -x = -40

=> x = 40

Therefore , the present age of the mother = 40 years

and the present age of the son = 1/2 × 40

= 20 years

I HOPE THIS ANSWER HELPS YOU PLEASE ADD MY ANSWER AS BRAINLIEST

Answer 2

Step-by-step explanation:

let sonu present age be 'x'

then sonu's mom present age = 2x

ten years ago age of sonu = x-10

ten years ago age of mom =2x-10

3(x-10)=2x-10

3x-30=2x-10

-30+10=2x-3x

-20=-1x

x= -20/-1

x= 20

Therefore, present sonu's age= 20

And,present mom's age = 40

please thank me