Question

A son's present age is half the present age of his mother. Ten years ago, the mother was thrice as old as her son. What are their present ages?

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Answer 1

Answer:

son's age is half mother's current age.

10 years ago, mother's age was thrice as old as the son. This will can be written as

x-10 = (x/2-10)*3

x-10 = 3x/2-30 or

2x-20 = 3x-60

Thus, 3x-2x = 60-20.

This gives x = 40, i.e. mother's current age is 40.

Son's current age is 1/2 of 40 = 20.

Answer 2

Answer:

Let the present age of the mother be x years

As the son's age is half the present age of his mother, therefore,

the present age of the son = 1/2x years

Ten years ago,

the age of the mother = (x-10) years

and the age of the son = (1/2x - 10) years

According to the problem ,

x - 10 = 3(1/2x - 10)

=> x - 10 = 3/2x - 30

=> 2x - 20 = 3x - 60 (multiplying both sides by 2)

=> 2x - 3x = 60+20

=> -x = -40

=> x = 40

Step-by-step explanation: