A son's present age is half the present age of his mother .Ten year ago , the mother was thrice as old as her son. What are their present ages?
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Let mother's current age be x. Then, son's present age will be x/2, since the son's age is half mother's current age.
10 years ago, mother's age was thrice as old as the son. This will can be written as
x-10 = (x/2-10)*3
x-10 = 3x/2-30 or
2x-20 = 3x-60
Thus, 3x-2x = 60-20.
This gives x = 40, i.e. mother's current age is 40.
Son's current age is 1/2 of 40 = 20.
10 years ago, mother's age was thrice as old as the son. This will can be written as
x-10 = (x/2-10)*3
x-10 = 3x/2-30 or
2x-20 = 3x-60
Thus, 3x-2x = 60-20.
This gives x = 40, i.e. mother's current age is 40.
Son's current age is 1/2 of 40 = 20.
Answered by
1
Answer:
therefore it gives x = 40, which is mother's current age is 40.
Son's current age is 1/2 of 40 = 20.
Step-by-step explanation:
here,in the given question, as per the data given we have to find a mothers and son's present ages as per the given conditions.
Let mother's present age be x.
Then, which clearly means
son's present age will be x/2,
as per the questoin, the son's age is half mother's current age.
consider, 10 years ago,
mother's age was thrice as old as the son.
which can be expressed as
x-10 = (x/2-10)*3
so on solving,
x-10 = 3x/2-30 or
2x-20 = 3x-60
hence, 3x-2x = 60-20.
therefore it gives x = 40, which is mother's current age is 40.
Son's current age is 1/2 of 40 = 20.
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