A sonar device on a submarine sents out a single and receive an echo 10 second lateral calculate the speed of speed of sound in water if the distance between object of a submarine is 4735 meters.
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Formula of velocity of echo is
V=2s/t
Therefore- v=2*4735/10
v=9470/10
v=947m/s
V=2s/t
Therefore- v=2*4735/10
v=9470/10
v=947m/s
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