a sonar device on submarine sends out a signal and recieves its echo 3s later. if the speed of the sound waves in sea water is 1530ms-1, find the depth of the sea bed below submarine?
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Answered by
5
time =2 sec
speed=1530 m/s
distace=2*D
2D=1530*2
3060m/2
=1530
speed=1530 m/s
distace=2*D
2D=1530*2
3060m/2
=1530
aanandhu98:
thanx
Answered by
3
2d = v * t
given
v = 1530ms-1
t = 3s
d = v * t /2
d = 1530*3/2
d =2295 m
given
v = 1530ms-1
t = 3s
d = v * t /2
d = 1530*3/2
d =2295 m
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