Question

A sonometer wire of length 0.73 m emits a sound
note of frequency 435 Hz. If length is shortened
to 0.725 m, how many beats/s will be produced
with a tuning fork of frequency 435 Hz?​

Answer 1

Answer:

Explanation:

s tension increases, frequency increases in the string as f∝  T

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where T is tension,

increase in tension in the string frequency of the string increases and as given in problem ,

beats decreases so frequency of string must be less than frequency of fork.

So, Beat =frequency of fork − frequency of string

10=480 Hz−f  s

​⇒frequency of string = 470 H  z

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