Question

a sonometer wire of length 50cm is stretched by keeping weight equivalent of 3.5 kg the fundamental frequency of vibrations is 125Hz determine the linear density of wire answer plz​

Answer 1

Answer:

Answered

53A sonometer wire of length 0.5 m is stretched by a weight of 5 kg. The fundamental frequency of vibration is 100Hz. Determine the linear density of material of wire. (Ans : 0.0049 kg/m)

2

Answer 2

The linear density of the wire is 2.195 * 10^-3 kg/m.

Given:

Length of a sonometer = 50cm , Mass = 3.5 kg and Fundamental Frequency = 125Hz.

To Find:

The linear density of the wire.

Solution:

Tension =  m * g

= 3.5 * 9.8

=34.3 N

Fundamental Frequency (n) = $\frac{1}{2l}\sqrt{\frac{T}{m} }$

⇒ Linear density m = $\frac{T}{4l^{2}n^{2} }$

= $\frac{34.3}{4*0.5^{2} *125^{2} }$

=$\frac{34.3}{15625}$

= 2.195 * 10^-3 kg/m.

∴ The linear density of the wire is 2.195 * 10^-3 kg/m.

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