a sonometer wire of length l vibrates in fundamental mode when excited by a tuning fork of frequency 416Hz.If the length is doubled keeping other things same, the string will vibrate with a frequency of
a. 416hz
b.208hz
c.832hz
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b) vibrate with a frequency of 208 Hz
According to the relation of the fundamental frequency of a string
ν=12lFμ−−√
where
l is the length of the string
F is the tension
μ is the linear mass density
We know that ν1 = 416 Hz, l1 = l and l2 = 2l.
v1∝1l1v1l1=v2l2(416)l=v2(2l)v2=208 Hz
According to the relation of the fundamental frequency of a string
ν=12lFμ−−√
where
l is the length of the string
F is the tension
μ is the linear mass density
We know that ν1 = 416 Hz, l1 = l and l2 = 2l.
v1∝1l1v1l1=v2l2(416)l=v2(2l)v2=208 Hz
Shesc:
Solution shows answer as 416Hz.ref.Concept of physics Hc verma pg323
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