A sonometer wire vibrates with a frequency of 500hz when the tension ist1 and with a frequency
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The Relation Between the frequency of the sonometer wire and the tensions are given below:-
f ∝ √T
So,
f1/f2 = √t1/t2 ⇒ 500/400 = √t1/t2 ⇒ √t2 = 4/5√t1
⇒ t2 = 16t1/25
so,
t1-t2= t1-16t1/25 = 9t1/25
therefore,
f/f' = √t1/t2 ⇒ f' = f√t'/t ⇒ f' = 500 x √9t1/25 /t1
⇒f'= 500 x √9/25 ⇒ 500 x 3/5
f'= 300HZ
this is your answer
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