A sound absorber attenuates the sound level by 20dB.
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The intensity decreases by a factor of. or, ΔL=10((I_(1))/(I_(0)) xx( I_(0))/(I_(2)))or,DeltaL = 10 log (I_(1)/(I_(2)))or,20 = 10 log((I_(1))/(I_(2))or,2 = log((I_(1))/(I_(2))or,(I_(1))/(I_(2)) = 10^(2)or,I_(2) = (I_(1))/(100).
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