Question

a sound has a speed of 330 metre per second and a frequency of 50 as a what is a possible distance between two points on the wave that has a phase difference of 60​

Answer 1

Explanation:

Any 2 points on wave that have phase difference of 60° are separated by a distance of 1.1 m.

Explanation:

The wavelength of this wave is

λ

=

v

f

=

330

m

s

50

s

=

6.6

m

Since

60

∘

is

1

6

t

h

of the total wavelength,

The possible distance between 2 points on wave that have phase difference of

60

°

=

6.6

m

⋅

1

6

=

1.1

m

I hope this helps,

Steve

PLEASE FOLLOW ME IF POSSIBLE PA AND I AM ASKING YOU FOR A LONG PERIOD OF TIME YOU ARE NOT AT ALL FOLLOWING ME