Question

A sound level i is greater by 3.0103 db from another sound of intensity 10 nw / cm^2 the absolute value of sound intensity of sound level i in w/m^2

Answer 1

Welcome there,

◆ Answer -
I' = 10718 W/m^2

◆ Explanation -
# Given -
I = 10×10^-9 W/m^2
I° = 10^-12 W/m^2

# Solution -
For reference sound,
Loudness = 10 × log(I/I°)
Loudness = 10 × log(10^-8/10^-12)
Loudness = 10 × log(10^4)
Loudness = 40 dB

For required sound,
L' = L + 3.0103
L' = 40.30103 dB

Intensity of required sound is calculated by -
I' = antilog(L'/10)
I' = antilog(40.30103/10)
I' = 10718 W/m^2

Therefore, absolute value of intensity of sound level is 10718 W/m^2.

Hope this helps you...