Physics, asked by ravi34287, 11 months ago

A sound source has an intensity level of 90dB. When the same 10 sound sources are sounded together, the intensity level becomes ...​

Answers

Answered by throwdolbeau
4

If the same 10 sound sources are sounded together, then the intensity level becomes 100 dB according to the calculation as follows :-

DISCUSSION :-

Known

TI₁ = 90 dB

n = 10

sound sources Was asked TIn =?

Answer :-  

The level of intensity of a sound source assume IT. Then, there are a number of sources of sound that produce sound together, then the level of intensity of the number of sounds can be searched using  

       \text{TI}_n = \text{TI}_1 + \text{10 log n}

So, if there are 10 sound sources the intensity level becomes

\text{TI}_n = \text{TI}_1 + \text{10 log n}

\text{TI}_n = 90 + \text{10 log 10}

\text{TI}_n = 90 + 10 \times 1

\text{TI}_n = 90 + 10

\text{TI}_n = 100 / \text{dB}

So, the level of intensity of the number of sounds is 100 dB.

Answered by Rohankaitake007
0

Answer:

TB is 10 b DB........

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