Physics, asked by yasirrajput1124, 1 month ago

A Sound ware has a wavelength of 0.20m. What is the phase difference between two points along the wave which are 0.85 m apart​

Answers

Answered by ojthapa10
3

Hope it helps. Thank you

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Answered by nirman95
5

General expression relating PHASE DIFFERENCE AND PATH DIFFERENCE is:

\boxed{\Delta \phi =  \dfrac{2\pi}{ \lambda}  \times \Delta d}

 \implies \Delta \phi =  \dfrac{2\pi}{ 0.2}  \times 0.85

 \implies \Delta \phi =  \dfrac{2\pi}{ 20}  \times 85

 \implies \Delta \phi =  \dfrac{\pi}{ 10}  \times 85

 \implies \Delta \phi =  8.5\pi

 \implies \Delta \phi =  8.5\pi \: radians

So, phase difference is 8.5π Radians.

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