Physics, asked by sanjivgayan5103, 7 months ago

A sound wave has a frequency of 3 kHz and wavelength 25 cm. The time taken by it to travel a distance of 1.5 km is :​

Answers

Answered by BrainlyPopularman
25

GIVEN :

Frequency of sound = 3 kHz = 3 × 10³ Hz

• Wavelength = 25 cm = 0.25 m

TO FIND :

• The time taken by it to travel a distance of 1.5 km = ?

SOLUTION :

• We know that –

 \\ \dashrightarrow \:  \large{\boxed { \bold{Velocity \:  \: of \:  \: sound = Frequency \times Wavelength}}} \\

• Put the values –

 \\ \implies { \bold{Velocity \:  \: of \:  \: sound = (3 \times  {10}^{3} ) \times (0.25)}} \\

 \\ \implies { \bold{Velocity \:  \: of \:  \: sound = (30 ) \times (25)}} \\

 \\ \implies { \bold{Velocity \:  \: of \:  \: sound = 750 \:  \dfrac{m}{s} }} \\

▪︎ We also know that –

 \\ \implies{ \boxed { \bold{Velocity  =  \:  \dfrac{Distance}{Time}} }} \\

• So that –

 \\ \implies { \bold{750  =  \:  \dfrac{1.5 \times  {10}^{3} }{Time}}} \\

 \\ \implies { \bold{750  =  \:  \dfrac{1500}{Time}}} \\

 \\ \implies { \bold{Time  =  \:  \dfrac{1500}{750}}} \\

 \\ \implies \large{ \boxed { \bold{Time  =2 \: sec}}} \\

Answered by BrainlyEmpire
12

\huge{\mathbb{\red{ANSWER}}}

\huge{\mathbb{\red{Given}}}

• Frequency of sound = 3 kHz = 3 × 10³ Hz

• Wavelength = 25 cm = 0.25 m

\huge{\mathbb{\red{To find}}}

• The time taken by it to travel a distance of 1.5 km = ?

\huge{\mathbb{\red{solutions}}}

• We know that –

$$\begin{lgathered}\\ \dashrightarrow \: \large{\boxed { \bold{Velocity \: \: of \: \: sound = Frequency \times Wavelength}}} \\\end{lgathered}$$

• Put the values –

$$\begin{lgathered}\\ \implies { \bold{Velocity \: \: of \: \: sound = (3 \times {10}^{3} ) \times (0.25)}} \\\end{lgathered}$$

$$\begin{lgathered}\\ \implies { \bold{Velocity \: \: of \: \: sound = (30 ) \times (25)}} \\\end{lgathered}$$

$$\begin{lgathered}\\ \implies { \bold{Velocity \: \: of \: \: sound = 750 \: \dfrac{m}{s} }} \\\end{lgathered}$$

▪︎ We also know that –

$$\begin{lgathered}\\ \implies{ \boxed { \bold{Velocity = \: \dfrac{Distance}{Time}} }} \\\end{lgathered}$$

\huge{\mathbb{\red{Given}}}

$$\begin{lgathered}\\ \implies { \bold{750 = \: \dfrac{1.5 \times {10}^{3} }{Time}}} \\\end{lgathered}$$

$$\begin{lgathered}\\ \implies { \bold{750 = \: \dfrac{1500}{Time}}} \\\end{lgathered}$$

$$\begin{lgathered}\\ \implies { \bold{Time = \: \dfrac{1500}{750}}} \\\end{lgathered}$$

$$\begin{lgathered}\\ \implies \large{ \boxed { \bold{Time =2 \: sec}}} \\\end{lgathered}$$

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