A sound wave in a certain fluid medium
is reflected at an obstacle to form a
standing wave. The distance between
two successive nodes is 3.75 cm. If the
velocity of sound is 1500 m/s, find the
frequency.
[Ans: 20 kHz]
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Answer:
20×10³ Hz
Explanation:
The distance between nodes referred to in the problem means that that
λ/2=3.8 cm, or
λ=0.076 m. Therefore, the frequency is
f=v/λ=(1500 m/s)/(0.076 m)≈20×103 Hz
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