Question

A sound wave of pressure amplitude 14 pascal propagates through the air medium.The normal pressure of air is 1.0times 10^(5)Nm^(2) .The difference between maximum and minimum pressure in the medium is​

Answer 1

pressure amplitude , $\Delta P_m$ = 14 Pascal = 14 × 10^5 N/m²

we know, standard equation of pressure wave is $P=\Delta P_mcos\left(\frac{2\pi t}{T}\right)$

so, maximum pressure = $+\Delta P_m$

minimum pressure = $-\Delta P_m$

so, difference between maximum pressure and minimum pressure in the medium is $\Delta P_m-(-\Delta P_m)$ = $2\Delta P_m$

= 2 × 14 × 10^5 N/m²

= 28 × 10^5 N/m²

= 2.8 × 10^6 N/m²

hence, answer is 2.8 × 10^6 N/m²