Question

A source emitting light of wavelengths 480 nm and 600 nm is used in a double-slit interference experiment. The separation between the slits is 0⋅25 mm and the interference is observed on a screen placed at 150 cm from the slits. Find the linear separation between the first maximum (next to the central maximum) corresponding to the two wavelengths.

Answer 1

Answer:

The linear separation between the first maximum (next to the central maximum) corresponding to the two wavelengths is 0.2mm

Explanation:

Given:

Wavelengths of the source of light=λ1=480nm

λ1=480×10⁻⁹ m and

λ2=600×10⁻⁹ m

Separation between the slits,

d=0.25 mm=0.25×10⁻³ m

Distance between screen and slit,

D=150 cm=1.5 m

We know that the position of the first maximum is given by

y=λD/d

The linear separation between the first maximum (next to the central maximum) corresponding to the two wavelengths = y2 − y1

y1= Dλ1/d= (1.5) x 480 x 10⁻⁹/0.25 x 10⁻³ =2.88 mm

y2=Dλ2/d=(1.5) x 600 x 10⁻⁹/0.25 x 10⁻³= 3.6mm

y2-y2=3.6-2.88= 0.2mm

Answer 2

Answer:

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