Question

A source is moving on a circle of radius 3 m with constant angular velocity ω = 5 rad/s. If the observer is at a distance 5 m from the centre of the circle, the time interval between the maximum and minimum frequency received by the observer is ?

[Fig and options are in attachment]​

Answer 1

option 3

Explanation:

given

radius = 3 m

angular velocity = 5 rad/s

so, angle it will make will surface

theta = cos^-1(3/5)

time interval,

formula for 2 pi rotation,

t =( 2*angle )/angular velocity

by putting the value

t = 2/5 * cos -1(3/5)

Answer = option 3

Answer 2

Answer:

$\frak\red{\underbrace{\underline{\bigstar\:\bf Required\:Answer:}}}$

Maximus is AT = B

Minimum is AT = A

$\\ \sf \: \purple{Time \: taken} \implies \:\pink{ t \: = \frac {2π}{w}}$

$\sf\: \: \: \pink = \orange{\frac{9 \: \ \cos(3 \div 5) }{5}}$

$\\ \green{\: \: \: \: = \frac{2}{5} \cos \: ( \frac{3}{5} ) }$

$\sf \: \blue {So \: the \: correct \: option \: is \: c}$