Question

A source is producing 1500 sound waves in 3 second. If the distance covered by a compression and an adjacent rarefaction be 68 cm, find (a) frequency, (b) wavelength, and (c) velocity, of the sound wave

Answer 1

number of vibrations produced by sound wave in 3 sec = 1500

we know, frequency is number of vibrations or oscillation in a second .

so, frequency = 1500/3 = 500 Hz

it is given that, distance covered by compression and adjacent refractions be 68cm

e.g., wavelength = 68cm

so, velocity of sound wave = wavelength × frequency

= 500 × 68 = 34000 cm/s or 340 m/s

hence, velocity of sound wave = 340m/s and frequency is 500Hz

Answer 2

Frequency =no. Of waves produce /time

=1500/3= 500hz

Wavelength = 2*68 =136cm

Velocity= 500*136/100

=5*136=680m/s