Question

A source of light emits photons 6 *10^15 per second having wavelength 4000 A^°. Another source of light of same intensity emits light of 6000 A^° ,then no. Of photons emitted per second

Answer 1

Answer:

9×10^15

Explanation:

P=E/T

P1=n1hv1/T1

P2=n2hv2/T2

since intensity is same

P1=P2

n2/T2=n1/T1 × (v1/v2)

n2/T2=6×10^15 ×( lambda2/lambda1)

n2/T2=6×10^15×(6000/4000)

n2/T2=9×10^15