Question

A source of light is at 12 cm from convex mirror. Now the distance of the object from the mirrors is double How much does the image move, if the radius of curvature of the mirrors is 12 cm?​

Answer 1

Explanation:

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A source of light is at 10 cm from a convex mirror and is then moved to a distance of 2 cm from the mirror. How much does the image move, if the radius of curvature of the mirror is 4.8 cm?

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Solution

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Correct option is B)

u=−10cm

u

2

=−2cm R

2

u−8

f=

2

R

=

2

2u−8

=2−u

By

f

1

=

u

1

+

v

1

⇒

v

1

1

=

f

1

−

u

1

1

=

2−u

1

−

u

1

1

=

60

31

=

2.u

1

−(

10

−1

)=

12

5

+

10

1

=

60

31

∴v

1

=

31

60

=1.930

when u

2

=−2cm

v

2

1

=

f

1

−

u

2

1

=

10

1

=

2u

10

−(−1/2)=

12

5

+

2

1

∴v

2

=1.09cm

v

1

−v

2

=1.935−1.09=1.935−1.1

=0.8cm

Answer 2

Answer:

f= 6cm , u=12×2=24cm, v= ?

A/Q:

1/u+1/v=1/f

1/24 +1/v=1/6

1/v= 1/6 - 1/24

1/v= (4 - 1)/24

1/v= 3/24

1/v=1/8

v=8cm

so the image will be form at 8cm