A source of sound is moving on a circular path with an angular speed of 4 rad/s as shown. The frequency of the source is 256 Hz. The maximumfrequency heared by a stationary observer at A is (velocity of sound in air is 332 m/s)
source
3m
observer
A
Far off
0 265 6 Hz
0 242 4 Hz
0 296 5 HZ
O 312.6 Hz
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Answer:
Velocity of source v
source
=rω=3×10=30m/s=v
s
The detector frequency of oscillation: f=5/s
Velocity of detector: v
d
=2πfa=2π×5×1=10π since a=1 as given
Minimum frequency recorded by the detector: f
min
=
v+v
s
v−v
d
=340×
330+30
330−10π
=340×
360
330−10×
7
22
=282Hz
Maximum frequency recorded by the detector: f
max
=
v−v
s
v+v
d
=340×
330−30
330+10π
=340×
300
330+10×
7
22
=410Hz
Explanation:
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