Question

A source of sound is moving with a velocity
of 50 m s' towards a stationary listener.
The listener measures the frequency of
the source as 1000 Hz. what will be the
apparent frequency of the source when
it is moving away from the listener after
crossing him? (velocity of sound in the
medium is 330 ms )
please answer this question.
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Answer 1

• The apparent frequency of the source when it is moving away from the listener after crossing him = 736.84 Hz

Explanation:

❶ When the source is moving towards the stationary listeners, the expression for apparent frequently is,

⟼ $\sf{n'\:=\:({\dfrac{v}{v\:-\:v_{s}}}})\:n$

⟼ $\sf{1000\:=\:({\dfrac{330}{330\:-\:50}}})\:n$

⟼ $\sf{n\:=\:({\dfrac{1000\:×\:280}{330}}})\:$

⟼ $\sf{n\:=\:848.48\:Hz}$

• The actual frequency of the sound is 848.48 Hz.

❷ When the source is moving away from the stationary listeners, the expression for apparent frequently is,

⟼ $\sf{n'\:=\:({\dfrac{v}{v\:+\:v_{s}}}})\:n$

⟼ $\sf({\dfrac{330}{330\:+\:50}})\:×\:848.48$

⟼ 736.84 Hz.

• The apparent frequency of the source when it is moving away from the listener after crossing him = 736.84 Hz