Question

A source of sound is placed at one end of an iron bar 2km long and two sounds are heard at the other end at an interval of 5.6 s. If the velocity of sound in air is 330m/s.
1. the time taken by sound to travel 2km in iron is
(A) 0.46s (B) 0.16 s
2. Velocity of sound in iron is
(A) 2348m/s (B)4348m/s

Answer 1

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Answer 2

1. The time taken by sound to travel 2km in iron is

(A) 0.46s

2. Velocity of sound in iron is

(B)4348m/s

Given that,

Velocity of sound in air (V) = 330m/s

Distance to travel (D) = 2km = 2000m       [1km = 1000m]

∴ Time taken to travel 2km in air (T) = D/V

= (2000/330)s = 6.06s

If we take time taken to travel 2km in iron as T'

Then, difference in the two times = (T - T' )

Given, this time difference = 5.6s

So, T - T' = 5.6

⇒ T' = T - 5.6 = 6.06 - 5.6 = 0.46s

Thus time taken by sound to travel 2km in iron is

(A) 0.46s

Velocity of sound in iron (V') = D/T'

= (2000/0.46) m/s

= 4347.83 m/s

≈ 4348 m/s

Thus speed of sound in iron is

(B) 4348 m/s