Physics, asked by Manasi7626, 8 months ago

A source of sound is travelling with a velocity of 30(m)/(s) towards a stationary observer. If actual frequency of source is 1000 Hz and the wind is blowing with velocity 20(m)/(s) in a direction at 60^@C with the direction of motion of source, then the apparent frequency heard by observer is (speed of sound is 340(m)/(s))

Answers

Answered by sarmahbarnali
0

Answer:

velocity of sound=30m/s

actual frequency=1000hz

velocity of the source=20m/s

therefore

observed frequency=(30/30-20)*1000

=300hz

Explanation:

use the formula when source would move towards the stationary observer:

observed frequency=(velocity of sound/velocity of sound-velocity of the source)*actual frequency

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