a source of sound produces 20 compressions and 20 rarefractions in 0.2 seconds.the distance between a compression and rarefaction is 50cm . find the wavelength,frequency and time period of the wave. please do answer it fast cuz tommorow is my finals.
Answers
Answered by
15
Wavelength is total path length between two rarefractions or compression
So, Wavelength = 50 × 2 = 100 cm
And, Frequency = 20/0.2
= 100 Hz
We know,
Time period = 1/f
= 1/100
= 0.01 second
So, Wavelength = 50 × 2 = 100 cm
And, Frequency = 20/0.2
= 100 Hz
We know,
Time period = 1/f
= 1/100
= 0.01 second
Answered by
5
Time period = 0.2 sec
Distance between a compression and rarefaction = 50 cm = 0.5 metres
Wavelength = 2 x Distance between a compression and rarefaction
= 2 x 0.5 = 1 meter
Frequency = No : of waves formed in 1 sec
20 waves are formed in 0.2 sec
No : of waves formed in 1 sec = 20 / 0.2 = 100 Hz
Frequency = 100 Hz
Frequency = 1 / Time period
Hence , time period = 1 / Frequency
= 1 / 100
= 0.01 sec
Distance between a compression and rarefaction = 50 cm = 0.5 metres
Wavelength = 2 x Distance between a compression and rarefaction
= 2 x 0.5 = 1 meter
Frequency = No : of waves formed in 1 sec
20 waves are formed in 0.2 sec
No : of waves formed in 1 sec = 20 / 0.2 = 100 Hz
Frequency = 100 Hz
Frequency = 1 / Time period
Hence , time period = 1 / Frequency
= 1 / 100
= 0.01 sec
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