a source of sound produces 20 compressions and 20 rarefactions in 0.2 seconds. The distance between a compression and the next rarefaction is 50cm. find the wavelength, frequency, timeperiod.
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We know that 20 compressions and 20 rarefactions make 20 oscillation
of the wave so the time period is 0.2/20=0.01 s
so frequency is f=1/T
1/0.01=100 Hz
distance between rarefaction and compression is 50 cm so distance between two rarefactions and two compressions is 2*50=100 cm=1 m
of the wave so the time period is 0.2/20=0.01 s
so frequency is f=1/T
1/0.01=100 Hz
distance between rarefaction and compression is 50 cm so distance between two rarefactions and two compressions is 2*50=100 cm=1 m
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Explanation:
We know that 20 compressions and 20 rarefactions make 20 oscillation
of the wave so the time period is 0.2/20=0.01 s
so frequency is f=1/T
1/0.01=100 Hz
distance between rarefaction and compression is 50 cm so distance between two rarefactions and two compressions is 2*50=100 cm=1 m
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