Question

A source of sound S emitting waves of frequency 100 Hz
and an observor O are located at some distance from each
other. The source is moving with a speed of 19.4 ms⁻¹ at an
angle of 60° with the source observer line as shown in the
figure. The observor is at rest. The apparent frequency
observed by the observer is (velocity of sound in air
330 ms⁻¹) [2015 RS]
(a) 103 Hz
(b) 106 Hz
(c) 97 Hz
(d) 100 Hz

Answer 1

Answer:

(a) 103 Hz

Explanation:

here is your answer. .....

hope it will help you....

Answer 2

ANSWER

Since the source has a component of velocity along SO, the apparent frequency observed by the observer will increase.

v: velocity of sound; vo=0 velocity of observer;vs=19.4×cos(600)=9.7 velocity of the source along SO

f0= frequency emitted by source

fapparent=f0(v−vsv−vo=100×(330−9.7330−0)=103.03