Question

A source of sound vibrating with a
frequency 510 Hz is in between a
stationary observer and
the foot of a wall. The source is
moving towards the wall with a​

Answer 1

Explanation:

ANSWER

When two sound waves of different frequency approach your ear, the alternating constructive and destructive interference causes the sound to be alternatively soft and loud - a phenomenon which is called "beating" or producing beats.

Here the source frequency is 510 Hz. When the source will start moving towards the wall with a velocity V

s

then the frequency of the source will be change to the stationary observer. The frequency of the beat will be:

Beat Frequency =

V

2×ν×V

s

Putting all the values in above equation will get,

Beat frequency =

340

2×510×3

=9 beats/s

Answer 2

Explanation
When two sound waves of different frequency approach your ear, the alternating constructive and destructive interference causes the sound to be alternatively soft and loud - a phenomenon which is called "beating" or producing beats.
Here the source frequency is 510 Hz. When the source will start moving towards the wall with a velocity V
s
​
then the frequency of the source will be change to the stationary observer. The frequency of the beat will be:

Beat Frequency =
V
2×ν×V
s
​

​

Putting all the values in above equation will get,
Beat frequency =
340
2×510×3
​
=
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