Question

a source of sound with 60m/s behind an observer also moving with same direction with 10m/s ,if source emit sound frequency 10khz then what will the observer have frequency?speed of sound is 350m/s

Answer 1

Answer:

11.7 KHZ

Explanation:

★ DOPPLER EFFECT ★ WAVE MOTION★

» REFER THE ATTACHMENT.

Answer 2

According to question;

$v_{o}$ = 10 Hz = 10⁴ kHz

$v_{s}$ = 60 m/s

c = 350 m/s m/s

We know that..

$v'\: = \: v_{o} \: \times \: \dfrac{c}{c \: - \: v_{s} }$

Here ..

• v' = Apparent frequency

• $v_{o}$ = Original frequency

• $v_{s}$ = Speed of source

• c = Speed of sound

Put the known values in above formula

=> v' = 10⁴ × $\dfrac{350}{350\:-\:60}$

=> v' = 10⁴ × $\dfrac{350}{290}$

=> v' = 10⁴ × 1.2069 Hz

=> v' = 12.069 × 10⁴ kHz

=> v' = 12 × 10⁴ kHz (approx.)

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Apparent frequency (v') = 12 × 10⁴ kHz.

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