Math, asked by aashkashukla18, 2 months ago

A space craft is at 452 m above the earth's surface. If it descends at the
rate of 5km per minute, what be its position after 9 hours?

Answers

Answered by ashy69963
1

Answer: (i) A space craft is at 4525 km above the earth's surface.

(ii) If it descends at the rate of 5 km per minute.

To find:

(i) Its position​ after 1 hour.

Solution:

We know that 1 hour = 60mins.

So, distance descended = (60*5) km

= 300km

New position after 1 hour = (4525-300) km

= 4225 km above earth's surface.

So, the new position is 4225km from earth's surface

Answered by SamrudhiDalvi
0

Answer:

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hope it helps :)

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