A space craft is at 4525 km above the earth’s sufface. If it descends
of 5 km per minute. What will be its position after 9 hours?
Answers
Step-by-step explanation:
Spacecraft at 4525km
It depends at the rate of 5km per minute
Position after 9hr =?
1hr = 60min
= 60×5 = 300
After 9hr = 300×9
= 2700km
Position after 9hrs = 4252-2700 = 1552km
Position after 9hrs will be 1552km above earth surface
Answer:
The position of the spacecraft is 1825km above the earth's surface after 9 hours
Step-by-step explanation:
Given,
The height of the spacecraft is 4525km above the earth's surface.
The distance with which it descends in a minute = 5km
To find,
The position of the spacecraft after 9 hours.
Solution:
We have 1 hour = 60min
Since distance traveled by spacecraft in 1min = 5km, distance travelled by the spacecraft in 60min = 5×60 = 300km
That is, the distance traveled by spacecraft in 1 hour = 300km
∴The distance traveled by spacecraft in 9 hours = 300×9 = 2700km
we can say that the spacecraft descended a distance of 2700km in 9 hours.
It traveled 2700km towards the earth's surface
∴ The position of the spacecraft is after 9 hours = 4525 - 2700 = 1825km above the earth's surface
Answer:
The position of the spacecraft is 1825km above the earth's surface after 9 hours
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