Question

A space craft is at 4525 km above the earth's surface.If it descends at the rate of 5 km per minute.What will be it's position​

Answer 1

Given:

(i) A space craft is at 4525 km above the earth's surface.

(ii) If it descends at the rate of 5 km per minute.

To find:

(i) Its position​ after 1 hour.

Solution:

We know that 1 hour = 60mins.

So, distance descended = (60*5) km

= 300km

New position after 1 hour = (4525-300) km

= 4225 km above earth's surface.

So, the new position is 4225km from earth's surface.

Answer 2

Answer:

= 4225 km above earth's surface. So, the new position is 4225km from earth's surface.

Step-by-step explanation:

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