a space rocket goes up with acceleration = 20m/s^2 in 1m. after 1m its fuel finishes but due to inertia it goes up like for a while calculate maximum height that rocket can achieve and after it from there how much time it will take to reach back to starting point
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The distance travelled by the rocket in 1 minute (60 s)
with a=10m/s² since a=a-g=10h=12×10×602×10×60²=18000mVelocity acquired =>v=10×60v=10×60=600m/safter 1 minute the rocket moves upward with velocity 600m/s and down ward.acceleration due to gravity till its velocity becomes zero0=(600)²−2gh₂=(600)²−2×10×h₂=(600)²−2×10×h₂=>h₂=18000m=18 kmTotal distance 18+18=36km
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with a=10m/s² since a=a-g=10h=12×10×602×10×60²=18000mVelocity acquired =>v=10×60v=10×60=600m/safter 1 minute the rocket moves upward with velocity 600m/s and down ward.acceleration due to gravity till its velocity becomes zero0=(600)²−2gh₂=(600)²−2×10×h₂=(600)²−2×10×h₂=>h₂=18000m=18 kmTotal distance 18+18=36km
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
abhi308:
bro acceleration is 20m/s2
NO since it is going up so it will oppose g=10 m/s2
so effective acceleration=20-10=10 m/s2
got it??
oh!!! that's where i was wrong
np plz mark as brainliest
it is difficult for student of 8th standard
ok
thanks for marking
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Hlo Every one this is the answer hope it will help you
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you just copied his ans
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