Question

a space shuttle burns fuel at the rate of 13,000kg in each second . find the force exerted by the fuel on the shuttle if in 2 seconds the shuttle experiences a change in momentum of 325,000kg x m/s

Answer 1

Explanation:

force=rate of change of momentum=change in momentum/time. ........(1)

where

change in momentum is 325000

so from 1

force=325000/2

force=162500N

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Answer 2

Answer:

The force exerted by the fuel on the shuttle is 1.625×10⁵N.

Explanation:

The force acting on a body in terms of change in momentum is given as,

$F=\frac{\Delta P}{t}$             (1)

Where,

F=force exerted by the fuel on the shuttle

ΔP=change in momentum experienced by the shuttle

t=total time required

From the question we have,

ΔP=325000=3.25×10⁵kg-m/s

t=2 second

By substituting the required values in equation (1) we get;

$F=\frac{3.25\times 10^5}{2}$

$F=1.625\times 10^5N$

Hence, the force exerted by the fuel on the shuttle is 1.625×10⁵N.