a spacecraft is at 4252km above the earth's surface.if it descends at the rate of 5km per minute.what will be its position after 9 hours
Answers
Answered by
3
Spacecraft at 4252km
It depends at the rate of 5km per min.
Position after 9hr= ?
1hr= 60minutes * 5
=60*5=300
After9 hr= 300*9
2700km
Position after 9hrs= 4252-2700= 1552km
Position after 9hrs will be 1552km above earth surface.
HOPE IT WILL HELP YOU!
MARK ME AS BRAINLIEST.
It depends at the rate of 5km per min.
Position after 9hr= ?
1hr= 60minutes * 5
=60*5=300
After9 hr= 300*9
2700km
Position after 9hrs= 4252-2700= 1552km
Position after 9hrs will be 1552km above earth surface.
HOPE IT WILL HELP YOU!
MARK ME AS BRAINLIEST.
Similar questions