Question

a spanner of 30cm long is used to loosen a nut by using a force of 45N calculate the moment of force on the nut.


answer it please​

Answer 1

Answer:

• 13.5Nm is the required moment of force.

Explanation:

According to the Question

It is given that,

• Force ,F = 45N
• Perpendicular Distance ,D = 30cm

we have to find the moment of force on the nut.

changing unit here

→ 30cm = 30/100 m

→ 0.3m

As we know that moment of force is calculated by

• Moment of Force = Force × Perpendicular Distance

By putting the value we get

$:\implies$ Moment of Force = 45× 0.3

$:\implies$Moment of Force = 13.5 Nm

• Hence, the moment of the force is 13.5Nm.

Answer 2

$\large\underline{\underline\color{red}{⧪{\pmb{\sf{ \: Given :-}}}}}$

• ➬ Length of spanner = 30 cm
• ➬ Force applied = 45 N

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$\large\underline{\underline\color{red}{⧪{\pmb{\sf{ \: To \: Find :-}}}}}$

• ➬ Moment force on the nut = ?

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$\large\underline{\underline\color{red}{⧪{\pmb{\sf{ \: Solution :-}}}}}$

❒ We know that :

$\large\green\bigstar{\underline{\boxed{\pink{\sf{Moment \: of \: Force = Force \times Distance}}}}}$

❒ Required converting :

1m = 100 cm .So,

$\blue{\leadsto}{\sf{30 cm = \cancel\dfrac{30}{100} = 0.3 m}}$

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❒ Now Moment of force :

$\large{:\longmapsto{\sf{Moment \: of \: force = Force \times Distance}}}$

$\large{:\longmapsto{\sf{ \: \: \: \: \: \: \: 45 \times 0.3}}}$

${\large\orange{:\longmapsto{\sf{ Moment \: of \: force = {\green{\underline{\sf{ 13.5 \: N}}}}}}}}$

❒ Therefore :

❝ Moment of force on the nut is 13.5 Nm . ❞

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