Question

A spanner of length 0.5m is used to open a nut by applying a minimum force of 5.0N Calculate the moment of force required.​

Answer 1

Given

• Perpendicular Distance = 0.5 m
• Force = 5 N

To Find

• Moment of force

Solution

☯ τ = Fd

• Where F is the force applied and D is the perpendicular distance from the fixed point

━━━━━━━━━━━━━━━━━━━━━━━━━

✭ According to the Question :

➞ τ = Fd

➞ τ = 5 × 0.5

➞ τ = 5 × 50 × 10⁻²

➞ τ = 2.5 Nm

∴ The moment of force is 2.5 Nm

━━━━━━━━━━━━━━━━━━━━━━━━━

Know More

• The moment of force is also called as the Torque
• It is represented by the Greek letter tau (τ)
• SI unit of torque is Nm

Answer 2

Given:-

$\bigstar$A spanner of length 0.5 m is used to open a nut by applying a minimum force of 5.0 N

To Find:-

$\bigstar$Calculate the moment of force required?

Solution:-

$\bigstar$We are given that, A spanner of length 0.5m and it is used to open a nut by the applying minimum force of 5.0 N .To Calculate the moment of force required, We are using formula:

$\hookrightarrow { \underline{ \boxed{ \sf \bigstar \: {Moment \: force = Distance \: \times \: Force \: \bigstar}}}}$

$\\ \hookrightarrow \sf \: Moment \: force = \tt \: 0.5 \times 5.0$

$\\ \hookrightarrow \sf \: Moment \: force = \tt \: 0.5 \times 5.0$

$\\ \hookrightarrow \sf \: Moment \: force = \tt \: 2.5$

$\bigstar$Hence, the moment force required is 2.5 Newton meter.